化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】
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化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】
化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】
化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】
你好!
数学之美团为你解答
积化和差公式
2 sinx siny = - cos(x+y) + cos(x - y)
∴ 2sin(π/4 +α) sin(π/4 - α)
= - cos(π/2) + cos(2α)
= cos(2α)
原式 = cos(2α) / [ cos(2α) sin(π/4 +α) ]
= 1/ sin(π/4 +α)
我猜我这条回答应该是提交失败...