(x-8000 )·(1+10%)= (1+35%)x-11000
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 19:56:02
x){B@Cہ\CmCU VAPTUB&Hv64\XtC=C[C=cSdYP UeL+l
[~qAbK gc
(x-8000 )·(1+10%)= (1+35%)x-11000
(x-8000 )·(1+10%)= (1+35%)x-11000
(x-8000 )·(1+10%)= (1+35%)x-11000
(x-8000 )·(1+10%)= (1+35%)x-11000
(x-8000)×1.1=1.35x-11000
1.1x-8800=1.35x-11000
1.35x-1.1x=11000-8800
0.25x=2200
x=8800
(x-8000 )·(1+10%)= (1+35%)x-11800 求X=?
(x)-2x·x-x-2x+1=0求x的值,
解下列方程!就三道!解下列方程.1、x/x-2 - 1-x²/x²-5x = 2x/x-3(x/x-2 - 1-x²不是一起的!)2、5x/x²+x-6 - 5-2x/x²-x-12=7x-10/x²-6x+8(5x/x²+x-6 - 5-2x不是一起的!)3、x-4/x-5 + x-8/x-9=x-7/x-
x*x*x*x+2008x*x+2007x+2008(提示:x*x*x-1=(x-1)*(x*x+x+1))
x+(x-1)+(x+1)+(x+10)+(x-10)=440
2道分式计算[(x+4)(x-2)]/x³+2x²+x÷[(x-2)/x·(x+4)/(x+1)]2x/(2x-1)+x/(x-2)=2
(2x-2)(x-1)=0 x(x-5)=5x-10
(X-X*20%-18-(X-X*20%-18)*10%=X*1/2-3(过程)
若1+x+x*x+x*x*x=0,求x+x*x+x*x*x+.+x(2000次幂)
请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
45x+10 =50X(x-1)
求函数Y=(X·X-2X-1)/(X·X-5X-6)的值域?
解方程:(13x-x²)/(x+1)·[x+(13-x)/(x+1)]=42.
两道初二数学计算题(1)x+6/x^2+2x+1-x+4/x^2+x=0(2)x+3/x÷x^2+3x/x-3·1/3-x
为什么3X-2(-X?(X-1)+5)=-3X +2 X? (X-1)-10
X×(x+1)=10
已知x除以(x*x-x+1)=7,求x*x除以(x*x*x*x+x*x+1)的值
(x+1分之x+6)-(x^+3x+2分之3x^+10x+4)+(x+2分之2x+1)=0,解这个方程