已知a²+ab-9=0,求(a²-b²/b)²÷(a²+ab)³乘(ab/b-a)²
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已知a²+ab-9=0,求(a²-b²/b)²÷(a²+ab)³乘(ab/b-a)²
已知a²+ab-9=0,求(a²-b²/b)²÷(a²+ab)³乘(ab/b-a)²
已知a²+ab-9=0,求(a²-b²/b)²÷(a²+ab)³乘(ab/b-a)²
a²+ab-9=0
a²+ab=9
[(a²-b²)/b]²÷(a²+ab)³*[ab/(b-a)]²
=[(a-b)(a+b)/b)]²÷[a(a+b)]³*[ab/(b-a)]²
=(a-b)²(a+b)²/b²÷a³(a+b)³ *a²b²/(a-b)²
=(a-b)²(a+b)²/b²*a²b²/(a-b)²*1/[a³(a+b)³]
=1/[a(a+b)]
=1/(a²+ab)
=1/9
你这什么乱七八糟的