作业帮-2（2x²y-2xy²）-[(-3x²y²+3x²y)+(3²y²-2xy²)],其中x=-1,y=2
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/30 15:06:35
![-2（2x²y-2xy²）-[(-3x²y²+3x²y)+(3²y²-2xy²)],其中x=-1,y=2](/uploads/image/z/1786127-23-7.jpg?t=-2%EF%BC%882x%26%23178%3By-2xy%26%23178%3B%EF%BC%89-%5B%28-3x%26%23178%3By%26%23178%3B%2B3x%26%23178%3By%29%2B%283%26%23178%3By%26%23178%3B-2xy%26%23178%3B%29%5D%2C%E5%85%B6%E4%B8%ADx%3D-1%2Cy%3D2)
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-2（2x²y-2xy²）-[(-3x²y²+3x²y)+(3²y²-2xy²)],其中x=-1,y=2
-2（2x²y-2xy²）-[(-3x²y²+3x²y)+(3²y²-2xy²)],其中x=-1,y=2
-2（2x²y-2xy²）-[(-3x²y²+3x²y)+(3²y²-2xy²)],其中x=-1,y=2
因为x=-1,y=2,所以：
-2（2x²y-2xy²）-[(-3x²y²+3x²y)+(3x²y²-2xy²)]
=-4x²y+4xy²-(3x²y-2xy²)
=-4x²y+4xy²-3x²y+2xy²
=-7x²y+6xy²
=xy(-7x+6y)
=-1*2*(7+12)
=-38