化简求值:[2x²-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]其中x=-1,y=½
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![化简求值:[2x²-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]其中x=-1,y=½](/uploads/image/z/1786399-7-9.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%9A%EF%BC%BB2x%26%23178%3B-%EF%BC%88x%2By%EF%BC%89%EF%BC%88x-y%EF%BC%89%EF%BC%BD%EF%BC%BB%EF%BC%882-x%EF%BC%89%EF%BC%88x%2B2%EF%BC%89%2B%EF%BC%88-y-2%EF%BC%89%EF%BC%882-y%EF%BC%89%EF%BC%BD%E5%85%B6%E4%B8%ADx%3D-1%2Cy%3D%26%23189%3B)
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化简求值:[2x²-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]其中x=-1,y=½
化简求值:[2x²-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]其中x=-1,y=½
化简求值:[2x²-(x+y)(x-y)][(2-x)(x+2)+(-y-2)(2-y)]其中x=-1,y=½
原式=(2x²-x²+y²)(4-x²+y²-4)
=(x²+y²)(y²-x²)
=y^4-x^4
=1/16-1
=-15/16
-16/27,不知道对不对,你再算算吧