y=sin(2x+π/2)+2sinαcosα+1的单调区间是?

一道三角恒等式证明题请证明sin(x+y)sin(x-y)=sin^2(x)-sin^2(y) y=[sin^2(x)]*[sin^2(x)]求导 求y=sin[sin(x^2)]的导数 3sin^2x+-2sin^2y=2sinx sin^2x+-sin^2y=? 判断单调性 y=sin(x-π/6) y=sin(-2x+π/3) 函数y=2sin(2x+α)(-π y=(sin x + COS x)^2 y=sinx+cosx可化成_____?A.2sin(x-π/4)；B.2sin(x+π/4)； C.√2sin(x-π/4)；D.√2sin(x+π/4)； 下列函数中,既为偶函数又在(0,π/2)内递增且是周期函数的是A y=sin x B y=cos x C y=sin|x| D y=|sin x| 化简sin(2x-y)*sin y+cos(2x-y)*sin y y=sin(π/2+πx)sinπx的最小正周期为 y=sin(π/2+πx)sinπx最小正周期 y=12sin(2x+π/6)+5sin(π/3-2x)最大值 y=12sin(2x+π/6)+5sin(π/3-2x)的最大值 y=sin(x+π/3)sin(x+π/2)化简 函数y=2sin(π/3-X)+sin(π/6+X)的最大值 周期y=sin(x+π/3)sin(x+π/2) 的最小正周期是多少 sin(x+y)sin(x-y)=k,求cos^2x-cos^2y