a²+b²+c²-ab-bc-ca=0,试说明:a=b=c
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a²+b²+c²-ab-bc-ca=0,试说明:a=b=c
a²+b²+c²-ab-bc-ca=0,试说明:a=b=c
a²+b²+c²-ab-bc-ca=0,试说明:a=b=c
a²+b²+c²-ab-bc-ca=(2a²+2b²+2c²-2ab-2bc-2ca)/2=(a²+b²-2ab+b²+c²-2bc+a²+c²-2ac)/2=(a-b)^2+(b-c)^2+(a-c)^2=0
(a-b)^2>=0 (b-c)^2>=0 (a-c)^2>=0
所以a=b=c