(1){(3x-2)/4+(2y-1)/5=2 {(2x+2)/4(3y+2)/5=0 (2){(x+y)/2+(x-y)/3=6 {2(x+y)-3x+3y=24(1){(3x-2)/4+(2y-1)/5=2{(2x+2)/4(3y+2)/5=0(2){(x+y)/2+(x-y)/3=6{2(x+y)-3x+3y=24(3){2x+3y=m{3x+5y=m+2的解满足x+y=2求m(1){(3x-2)/4+(2y-1)/5=2{(2x+2)/4-(3y+2)/5=0(2){
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