2-(3x-1)÷2=7÷2+(x-14)÷3
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2-(3x-1)÷2=7÷2+(x-14)÷3
2-(3x-1)÷2=7÷2+(x-14)÷3
2-(3x-1)÷2=7÷2+(x-14)÷3
原方程两边同乘以6,可得:
12-3(3x-1)=21+2(x-14)
即12-9x+3=21+2x-28
15-9x=2x-7
移项整理得:
11x=22
解得x=2
x-3/x²-1 ÷ (x-3)(x+1)/x²+2x+1 + 1/x+1,其中x=2
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