[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
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[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
=[5xy^2(x^2-3xy)+27x^6y^6]/(5xy^2)
=5xy^2(x^2-3xy)/(5xy^2)+27x^6y^6/(5xy^2)
=x^2-3xy+27x^5y^4/5
5-2√6
=3-2√6+2
=(√3-√2)²
所以√(5-2√6)=√3-√2
8-4√3
=6-2√12+2
=(√6-√2)²
所以2-√3=(8-4√2)/4=(√6-√2)²/4
所以√(2-√3)=(√6-√2)/2
这是什么题目= =
[5xy^2(x^2-3xy)-(-3x^2y^2)^3]/(5xy^2)
=(5x^3y^2-15x^2y^3+27x^6y^6)/5xy^2
=x^2-3xy+27x^5y^4/5
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