已知1²+2²+3²+4²···+n²=6分之1n(n+1)(2n+1),请利用公式计算(1)1²+2²+3²···+50²(2)26²+27²+28²+···+50²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 23:09:19
![已知1²+2²+3²+4²···+n²=6分之1n(n+1)(2n+1),请利用公式计算(1)1²+2²+3²···+50²(2)26²+27²+28²+···+50²](/uploads/image/z/1800832-40-2.jpg?t=%E5%B7%B2%E7%9F%A51%26%23178%3B%2B2%26%23178%3B%2B3%26%23178%3B%2B4%26%23178%3B%C2%B7%C2%B7%C2%B7%2Bn%26%23178%3B%3D6%E5%88%86%E4%B9%8B1n%EF%BC%88n%2B1%EF%BC%89%EF%BC%882n%2B1%EF%BC%89%2C%E8%AF%B7%E5%88%A9%E7%94%A8%E5%85%AC%E5%BC%8F%E8%AE%A1%E7%AE%97%EF%BC%881%EF%BC%891%26%23178%3B%2B2%26%23178%3B%2B3%26%23178%3B%C2%B7%C2%B7%C2%B7%2B50%26%23178%3B%EF%BC%882%2926%26%23178%3B%2B27%26%23178%3B%2B28%26%23178%3B%2B%C2%B7%C2%B7%C2%B7%2B50%26%23178%3B)
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