化简(1/(x-y)-1/(x+y))/(2y/(x^2-2xy+y^2))要具体的过程
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 22:28:50
x){3
C}
JM]]aT dUTjWijXujyn"} +b~
Bv<]iGӵ^62tR>lj[h0G,<=lPD:(JB]@{ɎzM
r@u p7H͞~
m l<;h9D=s1վ)P!"8áG "
化简(1/(x-y)-1/(x+y))/(2y/(x^2-2xy+y^2))要具体的过程
化简(1/(x-y)-1/(x+y))/(2y/(x^2-2xy+y^2))
要具体的过程
化简(1/(x-y)-1/(x+y))/(2y/(x^2-2xy+y^2))要具体的过程
(1/(x-y)-1/(x+y))/(2y/(x^2-2xy+y^2))
先对分子通分,公分母是(x-y)(x+y)
=([(x+y)-(x-y)]/[(x-y)(x+y)])÷[2y/(x-y)²]
=(2y/[(x-y)(x+y)])÷[2y/(x-y)²]
=(x-y)²/[(x-y)(x+y)]
约分,上下同时约去公因子(x-y)
=(x-y)/(x+y)
公式:x²-2xy+y²=(x+y)²
(1/(x-y)-1/(x+y))/(2y/(x^2-2xy+y^2))
=(1/(x-y)-1/(x+y))/(2y/(x-y)^2)
=(2y/(x-y)(x+y))/(2y/(x-y)^2)
=(x-y)/(x+y)
(x+y)(x-y)+4(y-1)
化简(2x+y)(2x-y)-(x+2y)(x-2y-1)
2x分之1- x+y分之1(2x分之x+y -x-y)化简
化简1/2x-1/x+y(x+y/2x-x-y)
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
1/(x-y)+1/(x+y)+2x/(x^2+y^2)+4x^3/(x^4+y^4)化简
化简:[(2x-y)平方+(2x+y)(2x-y)-4x(x-y+1)]÷2x
|x-y|+|y+1|=0化简
化简 3x(x^2-x-1)-(x+1)(3x^-x) X^3(x-y)+x(y-x)
y'/y=1/x
x^/y-x-y^/y-x化简.
化简x(y-x)-y(x-y)
计算:(1+ y/x-y )·(1- x/x+y)
感激不尽1.x,y满足(x-y-1)(x+y)
(1-y+x/y)除以y平方-x平方/x
证明:(y/x)+(x/y)+xy≥x+y+1
x+y分之1-(x+y)的平方x-y