sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3 - x)化简、、、
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sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3 - x)化简、、、
sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3 - x)
化简、、、
sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3 - x)化简、、、
原式=sinxcosπ/3+cosxsinπ/3+2sinxcosπ/3-2cosxsinπ/3-√3cosxcos2π/3-√3sinxsin2π/3
=1/2*sinx+√3/2*cosx+sinx-√3cosx+√3/2*cosx-3/2*sinx
=0
sin^2(π/3-x)+sin^2(π/6+x)
化简 sin²x+sin²(x+2π/3)+sin²(x-2π/3)
2sin(x+π/4)sin(x-π/4)=?
sin^2(π/4 +x)
sin(πx/2)求导
sin(x+π/3)用诱导公式化简如题sin(2x+π/3)和3sin(2x+π/3)
已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x)
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若tanx=2,则2sin平方x-3sin(π-x)sin(π/2-x)=
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sinx>sin(2π/3-x)(0
解不等式sin(2x+π/3)
sin(x+π/4)
已知函数f(x)=2根号3sin平方x-sin(2x-π/3)
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
当x趋向π lim (sin 3x )/( sin 2x) 的极限为?
化简:(sinα-cosα)^2+sin4α/2cos2α 化简:sin^2x+sin^2(x+2π/3)+sin^2(x-2π/3)
求sin^2(2x+π/3)的导数这样写为什么不对:[sin^2(2x+π/3)]'=[sin(2x+π/3)·sin(2x+π/3)]'=2[sin(2x+π/3)]'·sin(2x+π/3)=2cos(2x+π/3)·sin(2x+π/3)=sin(4x+2π/3)