若a∈(0,π/2),且cos(a+π/6)= (—根号2) / 4,则cosa=

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 00:55:22
若a∈(0,π/2),且cos(a+π/6)= (—根号2) / 4,则cosa=
x){ѽ4QG}#M';$k$jf t

若a∈(0,π/2),且cos(a+π/6)= (—根号2) / 4,则cosa=
若a∈(0,π/2),且cos(a+π/6)= (—根号2) / 4,则cosa=

若a∈(0,π/2),且cos(a+π/6)= (—根号2) / 4,则cosa=

因为:a∈(0,π/2),所以:a+π/6∈(π/6,2π/3),所以:sin(a+π/6)= =根号14/4
所以:cosa=cos[(a+π/6)-π/6]=cos(a+π/6)cosπ/6+sin(a+π/6)sinπ/6
=-根号2/4*根号3/2+根号14/4*1/2
=(根号14-根号6)/8