求方程5x^2+5y^2+8xy+2y-2x+2=0的实数解,
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求方程5x^2+5y^2+8xy+2y-2x+2=0的实数解,
求方程5x^2+5y^2+8xy+2y-2x+2=0的实数解,
求方程5x^2+5y^2+8xy+2y-2x+2=0的实数解,
5x^2+5y^2+8xy+2y-2x+2=0
则化为
4x^2+4y^2+8xy+x^2-2x+1+y^2+2y+1=0
化为:
4(x+y)^2+(x-1)^2+(y+1)^2=0
则须有
x+y=0
x-1=0
y+1=0
成立
则x=1
y=-1
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