分式约分:(y+z-x)/{x^2-(y+z)^2}

来源：学生作业帮助网编辑：作业帮时间：2024/11/20 00:32:01

$分式约分:(y+z-x)/{x^2-(y+z)^2}$

x��)�{��tO��]ˀ+�J�*� M��8#]G3Ψ�&�H�e�v6D��[�&�Q�[�[��Q� ��BEqI�Cl��@��|S

分式约分:(y+z-x)/{x^2-(y+z)^2}
分式约分:(y+z-x)/{x^2-(y+z)^2}

分式约分:(y+z-x)/{x^2-(y+z)^2}
(y+z-x)/{x^2-(y+z)^2}
=(y+z-x)/[(x-y-z)(x+y+z)]
=-(x-y-z)/[(x-y-z)(x+y+z)]
=-1/(x+y+z)