(m+2)n²-2n-1=(m+2)n²+mn+m+1

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(m+2)n²-2n-1=(m+2)n²+mn+m+1
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(m+2)n²-2n-1=(m+2)n²+mn+m+1
(m+2)n²-2n-1=(m+2)n²+mn+m+1

(m+2)n²-2n-1=(m+2)n²+mn+m+1
(m+2)n²-2n-1=(m+2)n²+mn+m+1
mn+m+1+2n+1=0
m(n+1)+2(n+1)=0
(n+1)(m+2)=0
n=-1 OR m=-2

-2n-1=mn+m+1
移项
mn+m+1+2n+1=0
提取公因式
m(n+1)+2(n+1)=0
会了吗?

(m+2)n²-2n-1=(m+2)n²+mn+m+1
m=-2
m+1=-1
所以,m=-2
n∈R