因式分解:(a²+3a-3)(a²+3a+1)-5
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因式分解:(a²+3a-3)(a²+3a+1)-5
因式分解:(a²+3a-3)(a²+3a+1)-5
因式分解:(a²+3a-3)(a²+3a+1)-5
令a的平方+3a=t,
则原式=(t-3)(t+1)-5=t的平方-2t-8=(t-4)(t+2)=(a的平方+3a-4)(a的平方+3a+2)
=(a+4)(a-1)(a+2)(a+1)