若sin²A+sin²C-sin²B=sinAsinC,且c=3a,则tanA
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若sin²A+sin²C-sin²B=sinAsinC,且c=3a,则tanA
若sin²A+sin²C-sin²B=sinAsinC,且c=3a,则tanA
若sin²A+sin²C-sin²B=sinAsinC,且c=3a,则tanA
是不是三角形ABC啊,否则无解.
总体思路:运用正弦定理得sinC=3sinA,代入原式计算