因式分解2x²+4x+2求解x²-4-12y²-12y-28x²-3xy+2y²
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因式分解2x²+4x+2求解x²-4-12y²-12y-28x²-3xy+2y²
因式分解2x²+4x+2求解
x²-4-12
y²-12y-28
x²-3xy+2y²
因式分解2x²+4x+2求解x²-4-12y²-12y-28x²-3xy+2y²
2x²+4x+2=2(x+1)^2
x²-4x-12=(x-6)(x+2)
y²-12y-28=(y-14)(y+2)
x²-3xy+2y²=(x-y)(x-2y)
2x^2+4x+2
=2(x^2+2x+1)
=2(x+1)^2
x^2-4x-12
=(x-6)(x+2)
y^2-12y-28
=(y-14)(y+2)
x^2-3xy+2y^2
=(x-y)(x-2y)= =过程呢这是交叉相乘法
e.g
(x^2+2x+1)
x^2 = x . x
1 = ...
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2x^2+4x+2
=2(x^2+2x+1)
=2(x+1)^2
x^2-4x-12
=(x-6)(x+2)
y^2-12y-28
=(y-14)(y+2)
x^2-3xy+2y^2
=(x-y)(x-2y)
收起
孩子,这都是基础练习题,你还是自己做吧。
不然你永远学不会。给你做个示范讲解一下吧
例: x²-4x-12
12=2*6 =3*4
6-2=4 6+2=8 4-3=1 4+3=7
所以取 6,2
x²-4-12 = (x-6)(x+2)