如图,在六边形ABCDEF中,∠B=∠E,∠A=∠D,BC‖eF1)求证:AF平行于CD2.求∠A+∠b+∠c的度数f ---------e / \ / \ a / \ d \ / b \----------- c
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![如图,在六边形ABCDEF中,∠B=∠E,∠A=∠D,BC‖eF1)求证:AF平行于CD2.求∠A+∠b+∠c的度数f ---------e / \ / \ a / \ d \ / b \----------- c](/uploads/image/z/1814885-53-5.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E5%85%AD%E8%BE%B9%E5%BD%A2ABCDEF%E4%B8%AD%2C%E2%88%A0B%3D%E2%88%A0E%2C%E2%88%A0A%3D%E2%88%A0D%2CBC%E2%80%96eF1%29%E6%B1%82%E8%AF%81%EF%BC%9AAF%E5%B9%B3%E8%A1%8C%E4%BA%8ECD2.%E6%B1%82%E2%88%A0A%2B%E2%88%A0b%2B%E2%88%A0c%E7%9A%84%E5%BA%A6%E6%95%B0f+++++---------e++++%2F+++++++++%5C++++%2F++++++++++%5C+a+%2F++++++++++++%5C+++++++++d+++%5C++++++++++++%2F++b++%5C-----------+++c)
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如图,在六边形ABCDEF中,∠B=∠E,∠A=∠D,BC‖eF1)求证:AF平行于CD2.求∠A+∠b+∠c的度数f ---------e / \ / \ a / \ d \ / b \----------- c
如图,在六边形ABCDEF中,∠B=∠E,∠A=∠D,BC‖eF
1)求证:AF平行于CD
2.求∠A+∠b+∠c的度数
f ---------e
/ \
/ \
a / \ d
\ /
b \----------- c
如图,在六边形ABCDEF中,∠B=∠E,∠A=∠D,BC‖eF1)求证:AF平行于CD2.求∠A+∠b+∠c的度数f ---------e / \ / \ a / \ d \ / b \----------- c
(1)
∵EF‖BC
∴∠EFC=∠BCF
∵四边形ABCF和CDEF内角和度数都是(4-2)*180°=360°
且∠A=∠D,∠B=∠E,∠EFC=∠BCF
∴∠AFC=∠DCF
∴AF‖CD(内错角相等,两直线平行)
(2)
∵∠AFC=∠DCF
∴∠C=∠BCF+∠DCF=∠BCF+∠AFC
∴∠A+∠B+∠C内角度数和即为四边形ABCF内角度数和,
为(4-2)*180°=360° (给点分啊,