作业帮[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/21 02:49:48
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[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]
[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]
[（4a²-4a)/(a²2a+1)]÷[a+1/(a-1)-(a-1)/(a+1)]×[1/(3a+3）]
原式=(4a(a-1)/2aaa+1)x（(a+1)(a-1)/4a）x（1/3(a+1)）
=(aa+1+2a)/(6aaa+3)