一道数学题``今天中午就要答案了`已知X1,X2是关于方程4X^2-(3M-5)-6M^2=0的俩个实数根,且X1/X2的绝对值=3/2,求 常数M的值

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一道数学题``今天中午就要答案了`已知X1,X2是关于方程4X^2-(3M-5)-6M^2=0的俩个实数根,且X1/X2的绝对值=3/2,求 常数M的值
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一道数学题``今天中午就要答案了`已知X1,X2是关于方程4X^2-(3M-5)-6M^2=0的俩个实数根,且X1/X2的绝对值=3/2,求 常数M的值
一道数学题``今天中午就要答案了`
已知X1,X2是关于方程4X^2-(3M-5)-6M^2=0的俩个实数根,且X1/X2的绝对值=3/2,求 常数M的值

一道数学题``今天中午就要答案了`已知X1,X2是关于方程4X^2-(3M-5)-6M^2=0的俩个实数根,且X1/X2的绝对值=3/2,求 常数M的值
有两个不同的实数根
所以(3m-5)^2+96m^2>0
105m^2-30m+25>0
此不等式恒成立
x1+x2=(3m-5)/4
x1*x2=-3m^2/2
|x1/x2|=3/2
所以x1=(3/2)x2或x1=-(3/2)x2
x1=(3/2)x2
分别代入x1+x2=(3m-5)/4
x1*x2=-3m^2/2
(5/2)x2=(3m-5)/4
(3/2)x2^2=-3m^2/2
x2=(3m-5)/10
所以(3/2)[(3m-5)/10]^2=-3m^2/2
[(3m-5)/10]^2+m^2=0
则(3m-5)/10=0,且m=0
不成立
x1=-(3/2)x2
分别代入x1+x2=(3m-5)/4
x1*x2=-3m^2/2
-(1/2)x2=(3m-5)/4
(3/2)x2^2=-3m^2/2
x2=-(3m-5)/2
所以-(3/2)[(3m-5)/2]^2=-3m^2/2
[(3m-5)/2]^2=m^2
(3m-5)/2=m或(3m-5)/2=-m
m=5或m=1

题错

X1和X2异号,故X1/X2的值为-3/2
X1/X2+X2/X1=(X1^2+X2^2)/X1X2
={(x1+x2)^2-2x1x2}/x1x2
=-1/24(3-5/m)^2-2=-3/2-2/3=-13/6
解出m=1或5