1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 17:20:02
x͐10EBI8@( .(P !@PmI=@ DFD $͡X" EЁ!o~Q~dSvxe32y6/3qZ|/N7|,'-{e&'^$lq^qZ9qPa}mj܍W1k&jק7NHZPdGjVY%Dc"8쥀U+7
1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做
1.a1=1,an+1=an+2n-1,求an
2.a1=1,an+1=2an+2n-1,求an
3.a1=1,an+1=3an+3n,求an
4.a1=1,an+1=3an+6,求an
就这4个,用累加或累乘的方法做
1.a1=1,an+1=an+2n-1,求an 2.a1=1,an+1=2an+2n-1,求an 3.a1=1,an+1=3an+3n,求an4.a1=1,an+1=3an+6,求an就这4个,用累加或累乘的方法做
a2-a1=1
a3-a2=3
a4-a3=5
.
an-an_1=2n-3
所以
an-a1=1+3+5+.+2n-3
=n-1+(n-1)(n-2)
=(n-1)平方
所以an=n^2-2n (n>1)
已知{an}满足a1=1.an=3*n+2An-1,求an
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列an,a1=1.an+1/an=n+2/n,求通项公式,
an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么意思?
an=a1+(n-1)d 和Sn=n(a1+an)/2中an是什么
数列{an}满足a1=1 an+1=2n+1an/an+2n
数列{an},a1=1,an+1=2an-n^2+3n,求{an}.
数列{an}中,a1=1,an+1/an=n/n+2,求an
a1=1,Sn=n^2an,求an
1.a1=1 an=a1+2a2+.(n-1)an-1求an2.an+a(n+1)=1/2,a1=1,求an
an+1 ,n+1是下表 ,an+1=an^3 a1=2 ,求an
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?
a1=1/2,an+1=an/an+2,求n/an的sn
数列an集合中,a1=2,an+1=an+(2n+1),求an.
数列{an}中,a1=35,an+1-an=2n-1,求an
已知数列an,a1=1 an+1-an=2的n次幂求an
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列{an},a1=2,an+1(下标)=an下标+n+1 求通项an下标