一元二次方程的求解 (4 20:50:31)(1)若ax²+x+8分之a=(2x+4分之1)²+m成立,则a= ,m= .(2)若实数x,y满足4x²+y²-4x+6y+1
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![一元二次方程的求解 (4 20:50:31)(1)若ax²+x+8分之a=(2x+4分之1)²+m成立,则a= ,m= .(2)若实数x,y满足4x²+y²-4x+6y+1](/uploads/image/z/1850822-62-2.jpg?t=%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E7%9A%84%E6%B1%82%E8%A7%A3+%284+20%3A50%3A31%29%EF%BC%881%EF%BC%89%E8%8B%A5ax%26%23178%3B%2Bx%2B8%E5%88%86%E4%B9%8Ba%3D%282x%2B4%E5%88%86%E4%B9%8B1%EF%BC%89%26%23178%3B%2Bm%E6%88%90%E7%AB%8B%2C%E5%88%99a%3D%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B+%2Cm%3D%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B%26%23160%3B+.%EF%BC%882%EF%BC%89%E8%8B%A5%E5%AE%9E%E6%95%B0x%2Cy%E6%BB%A1%E8%B6%B34x%26%23178%3B%2By%26%23178%3B-4x%2B6y%2B1)
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一元二次方程的求解 (4 20:50:31)(1)若ax²+x+8分之a=(2x+4分之1)²+m成立,则a= ,m= .(2)若实数x,y满足4x²+y²-4x+6y+1
一元二次方程的求解 (4 20:50:31)
(1)若ax²+x+8分之a=(2x+4分之1)²+m成立,则a= ,m= .
(2)若实数x,y满足4x²+y²-4x+6y+10=0,求x²+y²的值.
一元二次方程的求解 (4 20:50:31)(1)若ax²+x+8分之a=(2x+4分之1)²+m成立,则a= ,m= .(2)若实数x,y满足4x²+y²-4x+6y+1
(1)化简得:(a-4)x²+17/16-m=0
∵不论x取何值,等式都成立,
∴a-4=0,17/16-m=0
∴a=4,m=17/16
(2)整理得:(2x-1)²+(y+3)²=0
∴x=0.5,y=-3
∴x²+y²=9.25
我的数学是很好的哦!