已知a是实数,函数f(x)=x²(x-a) (1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程已知a是实数,函数f(x)=x²(x-a)(1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程(2)求f(x)在区间[0,2]上
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![已知a是实数,函数f(x)=x²(x-a) (1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程已知a是实数,函数f(x)=x²(x-a)(1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程(2)求f(x)在区间[0,2]上](/uploads/image/z/1859124-12-4.jpg?t=%E5%B7%B2%E7%9F%A5a%E6%98%AF%E5%AE%9E%E6%95%B0%2C%E5%87%BD%E6%95%B0f%28x%29%3Dx%26%23178%3B%28x-a%29+%281%29%E8%8B%A5f%27%281%29%3D3%2C%E6%B1%82a%E7%9A%84%E5%80%BC%E5%8F%8A%E6%9B%B2%E7%BA%BFy%3Df%28x%29%E5%9C%A8%E7%82%B9%281%2Cf%281%29%29%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E5%B7%B2%E7%9F%A5a%E6%98%AF%E5%AE%9E%E6%95%B0%2C%E5%87%BD%E6%95%B0f%28x%29%3Dx%26%23178%3B%28x-a%29%281%29%E8%8B%A5f%27%281%29%3D3%2C%E6%B1%82a%E7%9A%84%E5%80%BC%E5%8F%8A%E6%9B%B2%E7%BA%BFy%3Df%28x%29%E5%9C%A8%E7%82%B9%281%2Cf%281%29%29%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%282%29%E6%B1%82f%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%5B0%2C2%5D%E4%B8%8A)
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已知a是实数,函数f(x)=x²(x-a) (1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程已知a是实数,函数f(x)=x²(x-a)(1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程(2)求f(x)在区间[0,2]上
已知a是实数,函数f(x)=x²(x-a) (1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程
已知a是实数,函数f(x)=x²(x-a)
(1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程
(2)求f(x)在区间[0,2]上的最大值
已知a是实数,函数f(x)=x²(x-a) (1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程已知a是实数,函数f(x)=x²(x-a)(1)若f'(1)=3,求a的值及曲线y=f(x)在点(1,f(1))处的切线方程(2)求f(x)在区间[0,2]上
f(x)=x^2(x-a) =x^3-ax^2
f`(x)=3x^2-2ax
f'(1)=3
3-2a=3
a=0
f(x)=x^3
k=f`(x)=3x^2=3
f(1)=1
y-1=3(x-1)
所以切线方程式y=3x-2
2
(1)当a≤0时,f(x)max=f(2)=8-4a.
(2)当02时,f(x)max=0