2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
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2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
=(2001-2009)/8-(2001+8)/2009+8/2000-2009/2001
=-1-1-1+8/2000-8/2001
=-3+1/500250
=-2又500249/500250
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+82001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8
计算2001*(1/8-1/2009) 8*(1/2001-1/2009) 2009*(1/8-1/2001)
2001×(1/8-1/2009)+8×(1/2000-1/2009)-2009×(1/8+1/2001)
用简便方法 2001×(8分之1-2009分之1)+8×(2001分之1-2009分之1)-2009×(8分之1+2001分之1)+8
简便算法题2001*(1/8 - 1/2009)+8*(1/2001 - 1/2009)-2009*(1/8 + 1/2001)+81/8等等都是分数.不是除法
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8等于多少?
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8等于多少?
2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*9(1/8+1/2001)+8 简算
2001×(1÷8-1÷2009)+8×(1÷2001-1÷2009)-2009×(1÷8+1÷2001)+8累死人的简便计算······
求2001*(1/8-1/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8的简便方法是什么,要详细一点的.重谢.
2001*(1/8-9/2009)+8*(1/2001-1/2009)-2009*(1/8+1/2001)+8怎么算?要最简便的
2001x(8/1-1/2009)+8x(1/2001-1/2009)-2009x(1/8+1/2009)+8 怎么用简便方法计算
2001×(八分之一-2009分之一)+8×(2001分之1-2009分之1)-2009×(8分之1+2001分之1)+8要用简便方法
1/2009+2/2009-3/2009-4/2009+5/2009+6/2009-7/2009-8/2009+9/2009+10/2009-...-1999/2009-2000/2009+2001/2009+2002/2009
1+(-2)+3+(-4)+5+(-6)+.+2007+(-2008)+2009 1+(-2)+(-3)+4+5+(-6)+(-7)+8+.+2001+(-2002)
2001乘[8分之1减2009分之1]加8乘[2001分之1减2009分之1]减2009乘[8分之1加2001分之1﹞加8怎么简便计算高手们帮帮忙,回答的好加赏
2道数学题.(1).33·3/11+(-2.16)+9·8/17+(-3·21/25) (2).(-1)+(+2)+(-3)+(+4)+.+(-2007)+(+2008)+(-2009)+(+2001)