X's 在英文书籍中,看到数学符号X's,在书中是有这么一段:(X's or ε's,where X= 2ε-1,and so Sn = X1 +...+Xn = 2(ε1 +...+ εn)-n)这里还有一句,This test makes use of that approximation to assess the closeness of the fraction

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X's 在英文书籍中,看到数学符号X's,在书中是有这么一段:(X's or ε's,where X= 2ε-1,and so Sn = X1 +...+Xn = 2(ε1 +...+ εn)-n)这里还有一句,This test makes use of that approximation to assess the closeness of the fraction
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X's 在英文书籍中,看到数学符号X's,在书中是有这么一段:(X's or ε's,where X= 2ε-1,and so Sn = X1 +...+Xn = 2(ε1 +...+ εn)-n)这里还有一句,This test makes use of that approximation to assess the closeness of the fraction
X's 在英文书籍中,看到数学符号X's,
在书中是有这么一段:
(X's or ε's,where X= 2ε-1,and so Sn = X1 +...+Xn = 2(ε1 +...+ εn)-n)
这里还有一句,This test makes use of that approximation to assess the closeness of the fraction of 1's to 1/2 .
这里的1's有代表什么意思呢?
出处是《A STATIISTIICAL TEST SUIITE FOR RANDOM AND PSEUDORANDOM NUMBER GENERATORS FOR CRYPTOGRAPHIIC APPLIICATIIONS》,NIST Special Publication 800-22。

X's 在英文书籍中,看到数学符号X's,在书中是有这么一段:(X's or ε's,where X= 2ε-1,and so Sn = X1 +...+Xn = 2(ε1 +...+ εn)-n)这里还有一句,This test makes use of that approximation to assess the closeness of the fraction
这是一个数学公式 x和ε都表示未知数,如果ε你看着不爽可以用y,只不过是一个代号而已.题目中会给你n的值.Sn指n个数的和.如:
若 X= 2ε-1 则 Sn = X1 +...+Xn = 2[(ε1 +...+ εn)-n]