计算和分解因式.3Q计算(-3x)³×(-xy²)²(2x+3y)²-(2x-3y)²分解因式:a²b-b³x³-2x²+x
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![计算和分解因式.3Q计算(-3x)³×(-xy²)²(2x+3y)²-(2x-3y)²分解因式:a²b-b³x³-2x²+x](/uploads/image/z/1946718-54-8.jpg?t=%E8%AE%A1%E7%AE%97%E5%92%8C%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F.3Q%E8%AE%A1%E7%AE%97%28-3x%29%26%23179%3B%C3%97%EF%BC%88-xy%26%23178%3B%EF%BC%89%26%23178%3B%EF%BC%882x%2B3y%EF%BC%89%26%23178%3B-%EF%BC%882x-3y%EF%BC%89%26%23178%3B%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9Aa%26%23178%3Bb-b%26%23179%3Bx%26%23179%3B-2x%26%23178%3B%2Bx)
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计算和分解因式.3Q计算(-3x)³×(-xy²)²(2x+3y)²-(2x-3y)²分解因式:a²b-b³x³-2x²+x
计算和分解因式.3Q
计算(-3x)³×(-xy²)²
(2x+3y)²-(2x-3y)²
分解因式:a²b-b³
x³-2x²+x
计算和分解因式.3Q计算(-3x)³×(-xy²)²(2x+3y)²-(2x-3y)²分解因式:a²b-b³x³-2x²+x
(-3x)³×(-xy²)²
= - 27x³乘以x²乘以y的4次幂
=-27x的5次幂*y的4次幂
(2x+3y)²-(2x-3y)²
=[(2x+3y)+(2x-3y)]*[(2x+3y)-(2x-3y)]
=4x*6y
=24xy
a²b-b³=b(a²-b²)=b(a+b)(a-b)
x³-2x²+x=x(x²-2x+1)=x(x-1)²
(-3x)³×(-xy²)² =-27*X^3 * X^2*Y^4 =-27X^5*Y^4
(2x+3y)²-(2x-3y)² =[(2X+3Y)+(2X-3Y)]*[(2X+3Y)-(2X-3Y)]=(4X)(6Y)=24XY
a²b-b³=b(a² - b²)=b(a+b)(a-b)
x³-2x²+x=x(x²-2x+1)=x(x-1)²