实验测得某碳氢化合物A中,含碳百分之80,含氢百分之20,求该化合物的实验式.N(C):N(H) = 80%/12 :280%/12 :20%/1= 1 :3为什么是1;3?这个最简整数比怎么求出来的?我怎么计算的不对呀……该怎么求
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![实验测得某碳氢化合物A中,含碳百分之80,含氢百分之20,求该化合物的实验式.N(C):N(H) = 80%/12 :280%/12 :20%/1= 1 :3为什么是1;3?这个最简整数比怎么求出来的?我怎么计算的不对呀……该怎么求](/uploads/image/z/1958303-47-3.jpg?t=%E5%AE%9E%E9%AA%8C%E6%B5%8B%E5%BE%97%E6%9F%90%E7%A2%B3%E6%B0%A2%E5%8C%96%E5%90%88%E7%89%A9A%E4%B8%AD%2C%E5%90%AB%E7%A2%B3%E7%99%BE%E5%88%86%E4%B9%8B80%2C%E5%90%AB%E6%B0%A2%E7%99%BE%E5%88%86%E4%B9%8B20%2C%E6%B1%82%E8%AF%A5%E5%8C%96%E5%90%88%E7%89%A9%E7%9A%84%E5%AE%9E%E9%AA%8C%E5%BC%8F.N%EF%BC%88C%EF%BC%89%EF%BC%9AN%28H%29+%3D+80%25%2F12+%3A280%25%2F12+%3A20%25%2F1%3D+1+%3A3%E4%B8%BA%E4%BB%80%E4%B9%88%E6%98%AF1%EF%BC%9B3%3F%E8%BF%99%E4%B8%AA%E6%9C%80%E7%AE%80%E6%95%B4%E6%95%B0%E6%AF%94%E6%80%8E%E4%B9%88%E6%B1%82%E5%87%BA%E6%9D%A5%E7%9A%84%3F%E6%88%91%E6%80%8E%E4%B9%88%E8%AE%A1%E7%AE%97%E7%9A%84%E4%B8%8D%E5%AF%B9%E5%91%80%E2%80%A6%E2%80%A6%E8%AF%A5%E6%80%8E%E4%B9%88%E6%B1%82)
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