先化简再求值x-1分之x²+1-x分之1其中x=-2分之3
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先化简再求值x-1分之x²+1-x分之1其中x=-2分之3
先化简再求值x-1分之x²+1-x分之1其中x=-2分之3
先化简再求值x-1分之x²+1-x分之1其中x=-2分之3
原式=x^2/(x-1)+1/(1-x)
=(x^2-1)/(x-1)
=(x+1)(x-1)/(x-1)
=x+1
x=-3/2
原式=-3/2+1=-1/2
如果有疑问请点【评论】或者【追问】
(x-1)分之x²+(1-x)分之1
=(x-1)分之x²-(x-1)分之1
=(x-1)分之(x²-1)
=(x-1)分之[(x+1)(x-1)]
=x+1
=-2分之3+1
=-2分之1
明白请采纳,有疑问请追问!
有新问题请求助,谢谢!x+1分之x- x+1分之x+3乘x²+6...
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(x-1)分之x²+(1-x)分之1
=(x-1)分之x²-(x-1)分之1
=(x-1)分之(x²-1)
=(x-1)分之[(x+1)(x-1)]
=x+1
=-2分之3+1
=-2分之1
明白请采纳,有疑问请追问!
有新问题请求助,谢谢!
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