4x^2-(x^2+1)^2
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4x^2-(x^2+1)^2
4x^2-(x^2+1)^2
4x^2-(x^2+1)^2
原式=(2X)²-(X²+1)²
=(2X+X²+1)(2X-X²-1)
=-(X+1)²(X-1)²
利用平方差公式即可!
4x^2-(x^2+1)^2
=(2x+x^2+1)(2x-x^2-1)
=-(x+1)^2(x-1)^2
令x²=y
则4y-(y²+2y+1)
=-(y²-2y+1)
=-(y-1)²
=-(x²-1)²
4x^2-(x^2+1)^2
=[2x+(x^2+1)][2x-(x^2+1)]
=(x+1)^2[-(x^2-2x+1)]
=-(x+1)^2(x-1)^2
4x^2-(x^2+1)^2
=【2x+(x²+1)】【2x-(x²+1)】
=-(x+1)²(x-1)²
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