-a²+5ab+2b²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 13:19:56
![-a²+5ab+2b²](/uploads/image/z/1962061-61-1.jpg?t=-a%26%23178%3B%2B5ab%2B2b%26%23178%3B)
x}PJ@ .ÚMI?0Z(}Ro71^pΙsQpu]>- "B`|35|ʬ/r7v<;nu^ {P"C0dY\AL;H6bnm]`@m3z4-bU6ԯӃ:Y1N<}4}Ci\M_\C>kuzg.PtM
}{EA
/$
-a²+5ab+2b²
-a²+5ab+2b²
-a²+5ab+2b²
=-(( a-(5b+b*根号下33)/2) ))*(( a-(5b-b*根号下33)/2) ))
-a^2+5ab+2b^2=2ab-(a-2b)(a+b)
(a+b)(2b-a)+4ab
设-a²+5ab+2b²=0
把b看成常数,用公式法解出方程的两根a1、a2(我就不算了)
则原式=-(a-a1)(a-a2)
-a²+5ab+2b²
=-a²+5ab-25/4b²+33/4b²
=-(a+5/2b)²+33/4b²