(a+b)²+a(a+b)+(a+b)b+(a+b)³= 因式分解
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 04:58:21
![(a+b)²+a(a+b)+(a+b)b+(a+b)³= 因式分解](/uploads/image/z/1962081-9-1.jpg?t=%EF%BC%88a%2Bb%EF%BC%89%26%23178%3B%2Ba%EF%BC%88a%2Bb%EF%BC%89%2B%EF%BC%88a%2Bb%EF%BC%89b%2B%EF%BC%88a%2Bb%EF%BC%89%26%23179%3B%3D+%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3)
xK
0$el4EJHѥ n^)L2ijKByd2ʻFP]s^.VM
=#Uf֧..O\rGԃJ3tw)g* }j_
{_/{}m`Ҳ$5aq"RrBcsdTTXo%3zL+~u,D?Q9ʳ) 4v~EX
(a+b)²+a(a+b)+(a+b)b+(a+b)³= 因式分解
(a+b)²+a(a+b)+(a+b)b+(a+b)³= 因式分解
(a+b)²+a(a+b)+(a+b)b+(a+b)³= 因式分解
(a+b)² +a(a+b)+(a+b)b+(a+b)³
=a²+b²+2a+ab+ab+2b+a³+b³
=a²+b²+2a+2ab+2b+a³+b³
(a+b)²+a(a+b)+(a+b)b+(a+b)³
=(a+b)[(a+b)+a+b+(a+b)²]
=(a+b){(a+b)[(2+(a+b)]}
=(a+b)²(2+a+b)
(a + b)[a + b + a + b + a² + 2ab + b²]
= (a + b)[2a + 2b + a² + 2ab + b²]
= (a + b)[2(a + b) + (a + b)²]
= (a + b)²[2 + a + b]
(a+b)²+a(a+b)+(a+b)b+(a+b)³=(a+b)²+(a+b)(a+b)+(a+b)³=2(a+b)²+(a+b)³=(a+b)²(a+b+2)