数学归纳法证明 sinθ+sin2θ+sin3θ+...+sin(nθ)=数学归纳法证明:sinθ+sin2θ+sin3θ+...+sin(nθ)= { sin[(1/2)(n+1)θ] * sin[(1/2)nθ] } / sin[(1/2)θ]
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![数学归纳法证明 sinθ+sin2θ+sin3θ+...+sin(nθ)=数学归纳法证明:sinθ+sin2θ+sin3θ+...+sin(nθ)= { sin[(1/2)(n+1)θ] * sin[(1/2)nθ] } / sin[(1/2)θ]](/uploads/image/z/1962472-40-2.jpg?t=%E6%95%B0%E5%AD%A6%E5%BD%92%E7%BA%B3%E6%B3%95%E8%AF%81%E6%98%8E%26%238203%3B+sin%CE%B8%2Bsin2%CE%B8%2Bsin3%CE%B8%2B...%2Bsin%28n%CE%B8%29%3D%E6%95%B0%E5%AD%A6%E5%BD%92%E7%BA%B3%E6%B3%95%E8%AF%81%E6%98%8E%3Asin%CE%B8%2Bsin2%CE%B8%2Bsin3%CE%B8%2B...%2Bsin%28n%CE%B8%29%3D+%7B+sin%5B%281%2F2%29%28n%2B1%29%CE%B8%5D+%2A+sin%5B%281%2F2%29n%CE%B8%5D+%7D+%2F+sin%5B%281%2F2%29%CE%B8%5D)
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数学归纳法证明 sinθ+sin2θ+sin3θ+...+sin(nθ)=数学归纳法证明:sinθ+sin2θ+sin3θ+...+sin(nθ)= { sin[(1/2)(n+1)θ] * sin[(1/2)nθ] } / sin[(1/2)θ]
数学归纳法证明 sinθ+sin2θ+sin3θ+...+sin(nθ)=
数学归纳法证明:
sinθ+sin2θ+sin3θ+...+sin(nθ)= { sin[(1/2)(n+1)θ] * sin[(1/2)nθ] } / sin[(1/2)θ]
数学归纳法证明 sinθ+sin2θ+sin3θ+...+sin(nθ)=数学归纳法证明:sinθ+sin2θ+sin3θ+...+sin(nθ)= { sin[(1/2)(n+1)θ] * sin[(1/2)nθ] } / sin[(1/2)θ]