若实数a满足a²-2a-1=0,则3a²-6a+5=
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若实数a满足a²-2a-1=0,则3a²-6a+5=
若实数a满足a²-2a-1=0,则3a²-6a+5=
若实数a满足a²-2a-1=0,则3a²-6a+5=
由题可得a²-2a=1 又因为3a²-6a+5=3(a²-2a)+5=3+5=8