已知整式2a²+3a+1的值为6 ,求多项式6a²+9a+5
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已知整式2a²+3a+1的值为6 ,求多项式6a²+9a+5
已知整式2a²+3a+1的值为6 ,求多项式6a²+9a+5
已知整式2a²+3a+1的值为6 ,求多项式6a²+9a+5
整式2a²+3a+1的值为6
2a²+3a=5
6a²+9a+5
=3(2a²+3a)+5
=3×5+5
=20
2a²+3a+1=6,
6a²+9a+5=2a²×3+3a×3+1×(3+2)=(2a²+3a+1)×3+2=6×3+2=20
望采纳
已知整式2a²+3a+1=6;
则2a²+3a=5
所以6a²+9a+5
=3(2a²+3a)+5
=3×5+5=20