作业帮说明代数式[(x-y)²-(x+y)(x-y)]÷(-2y)+y的值,与y的值无关
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/26 11:35:57
![说明代数式[(x-y)²-(x+y)(x-y)]÷(-2y)+y的值,与y的值无关](/uploads/image/z/1963951-7-1.jpg?t=%E8%AF%B4%E6%98%8E%E4%BB%A3%E6%95%B0%E5%BC%8F%5B%28x-y%29%26%23178%3B-%28x%2By%29%28x-y%29%5D%C3%B7%28-2y%29%2By%E7%9A%84%E5%80%BC%2C%E4%B8%8Ey%E7%9A%84%E5%80%BC%E6%97%A0%E5%85%B3)
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说明代数式[(x-y)²-(x+y)(x-y)]÷(-2y)+y的值,与y的值无关
说明代数式[(x-y)²-(x+y)(x-y)]÷(-2y)+y的值,与y的值无关
说明代数式[(x-y)²-(x+y)(x-y)]÷(-2y)+y的值,与y的值无关
[(x-y)²-(x+y)(x-y)]÷(-2y)+y=[(x-y)（x-y-x-y)]÷(-2y)+y=-2y（x-y）÷(-2y)+y=x-y+y=x
化简以后只有x,
[(x-y)²-(x+y)(x-y)]÷(-2y)+y
=[x²+y²-2xy-x²+y²]÷(-2y)+y
=2y(y-x)÷(-2y)+y
=x-y+y
=x
故结果与y值无关。