(2a-b)(2b+a),(1-a)²-(a+2)²
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(2a-b)(2b+a),(1-a)²-(a+2)²
(2a-b)(2b+a),(1-a)²-(a+2)²
(2a-b)(2b+a),(1-a)²-(a+2)²
解
(2a-b)(2b+a)
=4ab+2a²-2b²-ab
=2a²-2ab²+3ab
(1-a)²-(a+2)²
=[(1-a)+(a+2)][(1-a)-(a+2)]
=3×(-2a-1)
=-6a-3
(2a-b)(2b+a)
=4ab+2a²-2b²-ab
=3ab+2a²-2b²
(1-a)²-(a+2)²
=1-2a+a²-(a²+4a+4)
=1-2a+a²-a²-4a-4
=-3-6a