(1)已知A={2,4,a2-2a+3},B={a+1,a2-4a+2,a2-3a+4,a2-5a+3},若A∪B={2,3},求A并B.(2)设A={x|x2+px-12=0},B={x|x2+qx+r=0},且A≠B,A∪B={-3,4},A∩B={-3},求p,q,r的值弄错了,不好意思,是:若A∩B={2,
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![(1)已知A={2,4,a2-2a+3},B={a+1,a2-4a+2,a2-3a+4,a2-5a+3},若A∪B={2,3},求A并B.(2)设A={x|x2+px-12=0},B={x|x2+qx+r=0},且A≠B,A∪B={-3,4},A∩B={-3},求p,q,r的值弄错了,不好意思,是:若A∩B={2,](/uploads/image/z/1979935-7-5.jpg?t=%EF%BC%881%EF%BC%89%E5%B7%B2%E7%9F%A5A%3D%EF%BD%9B2%2C4%2Ca2-2a%2B3%EF%BD%9D%2CB%3D%EF%BD%9Ba%2B1%2Ca2-4a%2B2%2Ca2-3a%2B4%2Ca2-5a%2B3%EF%BD%9D%2C%E8%8B%A5A%E2%88%AAB%3D%EF%BD%9B2%2C3%EF%BD%9D%2C%E6%B1%82A%E5%B9%B6B.%EF%BC%882%EF%BC%89%E8%AE%BEA%3D%EF%BD%9Bx%7Cx2%2Bpx-12%3D0%EF%BD%9D%2CB%3D%EF%BD%9Bx%7Cx2%2Bqx%2Br%3D0%EF%BD%9D%2C%E4%B8%94A%E2%89%A0B%2CA%E2%88%AAB%3D%EF%BD%9B-3%2C4%EF%BD%9D%2CA%E2%88%A9B%3D%EF%BD%9B-3%EF%BD%9D%2C%E6%B1%82p%2Cq%2Cr%E7%9A%84%E5%80%BC%E5%BC%84%E9%94%99%E4%BA%86%EF%BC%8C%E4%B8%8D%E5%A5%BD%E6%84%8F%E6%80%9D%EF%BC%8C%E6%98%AF%EF%BC%9A%E8%8B%A5A%E2%88%A9B%3D%EF%BD%9B2%2C)
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(1)已知A={2,4,a2-2a+3},B={a+1,a2-4a+2,a2-3a+4,a2-5a+3},若A∪B={2,3},求A并B.(2)设A={x|x2+px-12=0},B={x|x2+qx+r=0},且A≠B,A∪B={-3,4},A∩B={-3},求p,q,r的值弄错了,不好意思,是:若A∩B={2,
(1)已知A={2,4,a2-2a+3},B={a+1,a2-4a+2,a2-3a+4,a2-5a+3},若A∪B={2,3},求A并B.
(2)设A={x|x2+px-12=0},B={x|x2+qx+r=0},且A≠B,A∪B={-3,4},A∩B={-3},求p,q,r的值
弄错了,不好意思,是:若A∩B={2,3},求A∪B。
(1)已知A={2,4,a2-2a+3},B={a+1,a2-4a+2,a2-3a+4,a2-5a+3},若A∪B={2,3},求A并B.(2)设A={x|x2+px-12=0},B={x|x2+qx+r=0},且A≠B,A∪B={-3,4},A∩B={-3},求p,q,r的值弄错了,不好意思,是:若A∩B={2,
(1)你确定你第一题没抄错?你都知道了并集还要求什么呀?应该是A交B={2,3}吧.
将3代入A,得a=0或a=2,将a=0和a=2分别代入B,当a=0时,交集与题意不符,所以a=2,所以A并B={-3,-2,2,3,4}
(2)将x=-3代入A,求得p=-1;将x=-3和4分别代入B,求得q=-1和r=-12.
所以p=-1
q=-1
r=-12
(1)A∪B={-3,-2,2,3,4}
(2)p=-1
q=-1
r=-12