1.a²+4a+(a+b)²+10(a+b)+29=0,求3a²b-〔a²b-(3ab-a²b)-4a²〕-2ab的值2.|p+2|与q²-8q+16互为相反数,分解因式(x²+y²)-(pxy+q)
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![1.a²+4a+(a+b)²+10(a+b)+29=0,求3a²b-〔a²b-(3ab-a²b)-4a²〕-2ab的值2.|p+2|与q²-8q+16互为相反数,分解因式(x²+y²)-(pxy+q)](/uploads/image/z/1980141-69-1.jpg?t=1.a%26sup2%3B%2B4a%2B%28a%2Bb%29%26sup2%3B%2B10%28a%2Bb%29%2B29%3D0%2C%E6%B1%823a%26sup2%3Bb-%E3%80%94a%26sup2%3Bb-%283ab-a%26sup2%3Bb%29-4a%26sup2%3B%E3%80%95-2ab%E7%9A%84%E5%80%BC2.%7Cp%2B2%7C%E4%B8%8Eq%26sup2%3B-8q%2B16%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%28x%26sup2%3B%2By%26sup2%3B%29-%28pxy%2Bq%29)
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