已知函数f x=Asin(3x+9)(A>0.x∈—(+∞,-∞),0
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已知函数f x=Asin(3x+9)(A>0.x∈—(+∞,-∞),0
已知函数f x=Asin(3x+9)(A>0.x∈—(+∞,-∞),0
(2)求f(x)的解析式;
(3)r若f(2/3 α+12/5)=12/5,求sinα.
已知函数f x=Asin(3x+9)(A>0.x∈—(+∞,-∞),0
(1)T=2pi/3,3是x前面的系数
(2)最大值为A,所以A=4
f(x)=4sin(3x+9)
(3)f(2/3 α+12/5)=12/5
4sin(2α+36/5+9)=12/5
sin(2α+81/5)=3/5
你确定题目是对的?
α=[arcsin(3/5)-81/5]/2
sinα=-0.9971
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