2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y²º¹º+y的值?
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2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y²º¹º+y的值?
2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y²º¹º+y的值?
2(x-1)²+▏x+2y+1▕=0,求½x²ºº³y²º¹º+y的值?
绝对值和完全平方非负
x-1=0
x=1
x+2y+1=0
1+2y+1=0
y=-1
½x²ºº³y²º¹º+y
=1/2×1×(-1)^2010-1
=1/2-1
=-1/2
因为2(x-1)²+▏x+2y+1▕=0,而(x-1)²>=0,|x+2y+1|>=0,所以有:
(x-1)²=0,|x+2y+1|=0,即x=1,x+2y+1=0,也即x=1,y=-1.
故:½x²ºº³y²º¹º+y=(1/2)*1^2003*(-1)^2010-1=1/2-1=-1/2.