已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
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已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
丨4x+3y-6丨+[2x+y-4]^2=0,
说明
4x+3y-6=0
且 2x+y-4=0
所以
y=(4x+3y-6)-2(2x+y-4)=2
x=1
2x-3y=-4
看不清题目啊
丨4x+3-6丨+[2x+y-4]^2=0
因为非负数和为0,故丨4x+3-6丨=0,[2x+y-4]^2=0
奇色幻想,你好!
因为任何数的绝对值和平方都大于等于0
因此4x+3-6=0,x=3/4
2x+y-4=0
3/2+y-4=0
y=5/2
那么2x-3y=3/2-15/2=-6
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