已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/19 16:39:03
已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
xN0_;6;Q^h`^679^t[" xWzii[cM&+](.0!Ҷ{:@w3Jc-m[C|/%4x%h@^Lz/@&qP|  S=,Ev+va6z%E"b'#}&2S[D_o?kHp{KŴb8N$H>sb!g,"5s%ъFE'%gds#LLp2Jº +E;h?'d h>'@",

已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值

已知丨4x+3-6丨+[2x+y-4]^2=0,求2x-3y的值
丨4x+3y-6丨+[2x+y-4]^2=0,
说明
4x+3y-6=0
且 2x+y-4=0
所以
y=(4x+3y-6)-2(2x+y-4)=2
x=1
2x-3y=-4

看不清题目啊

丨4x+3-6丨+[2x+y-4]^2=0
因为非负数和为0,故丨4x+3-6丨=0,[2x+y-4]^2=0

奇色幻想,你好!
因为任何数的绝对值和平方都大于等于0
因此4x+3-6=0,x=3/4
2x+y-4=0
3/2+y-4=0
y=5/2
那么2x-3y=3/2-15/2=-6