若x,y满足y=√1-2x+√(x-1)*2-√2x-1,求xy的平方根,

若变量x,y满足约束条件{x>=-1;y>=x;3x+2y 若xy满足x²+2x+y-2√y-1=-1,求xy, 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y 设x,y满足约束条件x+y>=1,x-y>=-1,2x-y 变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y 若实数x,y满足x^2+6x+(√x-y+1) +9=0.求代数式(（1/x-y)+(1/x+y))除以y/x^2-y^2 的值（要求对代数式先化简,再求值） 若实数x,y满足x的平方+2√3x+根号（x+y+1）+3=0,求代数式(1/x-y+1/x+y)÷y/（x²+y²）重点是代入部分啊 已知实数x,y满足y=|x-1|若x+2y 若正数x,y满足x²-y²=2xy,求（x-y)/(x+y)的值答案为√2-1 已知实数x,y,满足x-√x-1=√y+3-y,则x+y最大值是? 若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y= 方程组2x+y=1-m...x+2y=2中,若未知数x,y满足x+y 若x,y满足|x-y+1|+(x+y+3)^2=0则x^2-y^2= 若实数x,y满足x-y+1》=0,x+y>=0,x 若实数x,y满足x-y+1>=0,x+y>=0,x 已知x,y满足约束条件：x-y+1>=0,x+y-2>=0,x 已知有理数x,y满足关系式y=[√(x^2-1)+√(1-x^2)/(x-1)]-x+2,求x∧y的值. 求救!已知实数x,y满足下面关系式:y=√x^2-1+√1-x^2/x-1-x+2,求x^y的值