作业帮计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
来源：学生作业帮助网 编辑：作业帮 时间：2024/12/03 05:30:17
![计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy](/uploads/image/z/1988148-12-8.jpg?t=%E8%AE%A1%E7%AE%97%2C%E3%80%901%E3%80%91%5Bx%28x%5E2-2x%2B3%29-3x%5D%C3%B71%2F2x%5E2+%E3%80%902%E3%80%91%5B%282xy-3%29%28%E3%80%901%E3%80%91%5Bx%28x%5E2-2x%2B3%29-3x%5D%C3%B71%2F2x%5E2%E3%80%902%E3%80%91%5B%282xy-3%29%282xy%2B3%29%2B%28xy%2B3%5E2%5D%C3%B7xy)
xő;N@@bE(;"'
;6F8T9T\ -()1X#BC57~m۷6W]HD1 EJ[Gt >xb aF<֭SB3{d @4;b {4Ay`n|> rqQEVMlt c[-sQ:]bH/\$ ) TdD9f(9qFf $qTL3K ǵUNŷWNraw902W% , ~)9ş 5^N}Ǭ
计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(
【1】[x(x^2-2x+3)-3x]÷1/2x^2
【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
计算(x+1)(x+2)(x+3)(x+4)
计算：（x+1)(x-2)(x-3)(x-6)
计算 x(x+3)-(x-1)(x-2）
如何计算 (x+1)(x+2)(x+3)(x+4)
计算(X-1)(X-2)(X-3)(X-4)
(x-1)(x-2)(x-3)(x-4)-24计算
计算：x/(x-1)-(x+3)/(x^-1)*(x^2+2x+1)/(x+3)
计算:[(x^2 - 4)/(x^2 - x - 6) + (x+2)/(x-3)] / (x+1)/(x-3)
计算：1-2x+x^2/x-x^3*xy+x^2y/x-x^2
x/x-3-5x/x^2-x-6计算
x(x-2)(2x-3)计算
计算： (x+3)(x²-x-2)
计算 (x+3)(x²-x-2)
2x*4x-3x计算
计算:x/x-2 - 5x/x²-x-6计算:x/x-3 - 5x/x²-x-6
计算3x^3-(x^2 +2x)(3x-1)-3(x+5)(x-2)
2x/x-1+1/x+3-3x+5/x^2+2x-3计算,
计算 2+x+3/x-1*x^2-2x+1/x^2+6x+9