已知2x+3/x(x-1)(x+2)=(A/x)+(B/x-1)+(C/x+2).(A.B.C是常数),求A.B.C的值
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已知2x+3/x(x-1)(x+2)=(A/x)+(B/x-1)+(C/x+2).(A.B.C是常数),求A.B.C的值
已知2x+3/x(x-1)(x+2)=(A/x)+(B/x-1)+(C/x+2).(A.B.C是常数),求A.B.C的值
已知2x+3/x(x-1)(x+2)=(A/x)+(B/x-1)+(C/x+2).(A.B.C是常数),求A.B.C的值
(2x+3)/[x(x-1)(x+2)]=A/x+B/(x-1)+C/(x+2)
=[A(x^2+x-2)+B(x^2+2x)+C(x^2-x)]/[x(x-1)(x+2)]
=[(A+B+C)x^2+(A+2B-C)x-2A]/[x(x-1)(x+2)]
可得:
A+B+C=0
A+2B-C=2
-2A=3
A=-3/2
B=5/3
C=-1/6
左边=[2*(x-1)(x+2)+3]/x(x-1)(x+2)
=[(2x-2)(x+2)+3]/x(x-1)(x+2)
=(2x^2+2x-4+3)/x(x-1)(x+2)
右边=[A(x-1)(x+2)+Bx(x+2)+Cx(x-1)]/x(x-1)(x+2)
=[(Ax-A)(x+2)+Bx^2+2Bx+Cx^2-Cx]/x(x-1)(x+2)
=(A...
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左边=[2*(x-1)(x+2)+3]/x(x-1)(x+2)
=[(2x-2)(x+2)+3]/x(x-1)(x+2)
=(2x^2+2x-4+3)/x(x-1)(x+2)
右边=[A(x-1)(x+2)+Bx(x+2)+Cx(x-1)]/x(x-1)(x+2)
=[(Ax-A)(x+2)+Bx^2+2Bx+Cx^2-Cx]/x(x-1)(x+2)
=(Ax^2+2Ax-Ax-2A+Bx^2+2Bx+Cx^2-Cx)/x(x-1)(x+2)
=[(A+B+C)x^2+(A+2B-C)x-2A]/x(x-1)(x+2)
所以
(A+B+C)X^2=2X^2
(A+2B-C)X=2X
-2A=-4+3=-1
所以A+B+C=2
A+2B-C=2
A=1/2
解得A=1/2,B=1,C=1/2
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