作业帮若/y+5/+(x-2)^2=0,求-3(2x-y)-[6x+2y-(10x-8y)]的值
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![若/y+5/+(x-2)^2=0,求-3(2x-y)-[6x+2y-(10x-8y)]的值](/uploads/image/z/1989865-1-5.jpg?t=%E8%8B%A5%2Fy%2B5%2F%2B%28x-2%29%5E2%3D0%2C%E6%B1%82-3%282x-y%29-%5B6x%2B2y-%2810x-8y%29%5D%E7%9A%84%E5%80%BC)
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若/y+5/+(x-2)^2=0,求-3(2x-y)-[6x+2y-(10x-8y)]的值
若/y+5/+(x-2)^2=0,求-3(2x-y)-[6x+2y-(10x-8y)]的值
若/y+5/+(x-2)^2=0,求-3(2x-y)-[6x+2y-(10x-8y)]的值
因为绝对值大于等于0
y+5=0
y=-5
x-2=0
x=2
-6x+3y-(6x+2y-10x+8y)
=-6x+3y-(10y-4x)
=-6x+3y-10y+4x
=-2x-7y
将x=2 y=-5代入
=-4+35
=31