2(ax²—x³)+b(x²+ax)=ax³—3x²-cx 求a+b+c的值
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2(ax²—x³)+b(x²+ax)=ax³—3x²-cx 求a+b+c的值
2(ax²—x³)+b(x²+ax)=ax³—3x²-cx 求a+b+c的值
2(ax²—x³)+b(x²+ax)=ax³—3x²-cx 求a+b+c的值
2(ax²—x³)+b(x²+ax)=ax³—3x²-cx
2ax²-2x³+bx²+abx=ax³-3x²-cx
-2x³+(2a+b)x²+abx=ax³-3x²-cx
∴-2=a 2a+b=-3 ab=c
a=-2
b=1
c=-2
∴a+b+c=-2+1-2=-3
d