已知根号9/4-a+(b-1/4)²=0,求(a-b)/(根号a+根号b)+(a+b-2根号ab)/(根号a-根号b)
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已知根号9/4-a+(b-1/4)²=0,求(a-b)/(根号a+根号b)+(a+b-2根号ab)/(根号a-根号b)
已知根号9/4-a+(b-1/4)²=0,求(a-b)/(根号a+根号b)+(a+b-2根号ab)/(根号a-根号b)
已知根号9/4-a+(b-1/4)²=0,求(a-b)/(根号a+根号b)+(a+b-2根号ab)/(根号a-根号b)
√9/4-a+(b-1/4)²=0,则 ==> :√9/4-a=0 ==> a=9/4
(b-1/4)²=0,则 ==> b-1/4=0==>b=1/4
(a-b)/(√a+√b)+(a+b-2√ab)/(√a-√b)
=(a-b)(√a-√b)/(√a+√b)(√a-√b)+(√a-√b)²/(√a+√b)(√a-√b)
=(√a-√b)+(√a-√b)
=2√a
a